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用因式分解的思想作多项式的除法题
[(x^2+y^2)^2-4x^2·y^2]÷(x^2-y^2)
人气:110 ℃ 时间:2020-04-20 18:22:58
解答
〔(x^2+y^2)^2-4x^2·y^2〕÷(x^2-y^2)
〔x^4+y^4-2x^2·y^2〕÷(x^2-y^2)
=(x^2-y^2)^2÷(x^2-y^2)
=(x+y)(x-y)
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