(a+b)²=49,(a-b)²=9,求a²+b²,ab的值
人气:463 ℃ 时间:2020-03-29 07:21:49
解答
(a+b)²+(a-b)²
=a^2+2ab+b^2+a^2-2ab+b^2
=2a^2+2b^2
=2(a^2+b^2)=58
a^2+b^2=29
(a+b)²-(a-b)²=a^2+2ab+b^2-a^2+2ab-b^2
=4ab=40
ab=10
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