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求证(tana)2次方-(sina)2次方=(tana)2次方乘(sina)2次方
人气:254 ℃ 时间:2020-04-02 16:16:36
解答
∵(sinα/cosα)cosα=sinα, ∴tanαcosα=sinα, ∴(tanα)^2(cosα)^2=(sinα)^2,
∴(tanα)^2[1-(sinα)^2]=(sinα)^2,
∴(tanα)^2-(tanα)^2(sinα)^2=(sinα)^2,
∴(tanα)^2-(sinα)^2=(tanα)^2(sinα)^2.
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