把x=1代入方程
1^3-(2m+1)*1^2+(3m+2)*1-m-2
=1-2m-1+3m+2-m-2
=0
所以x=1是方程的解
x^3-(2m+1)x^2+(3m+2)x-m-2
=x^3-x^2-2mx^2+2mx+mx+2x-m-2
=x^2(x-1)-2mx(x-1)+m(x-1)+2(x-1)
=(x-1)(x^2-2mx+m+2)