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计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2
人气:257 ℃ 时间:2020-03-27 06:51:47
解答
x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2 =(x-2)(x-3)/(x-3)(x-1)+(x-3)(x-1)/(x-1)²-(x-4)(x+1)/(x+1)(x-1)=(x-2)/(x-1)+(x-3)/(x-1)-(x-4)/(x-1)=(x-2+x-3-x+4)/(x-1)=(x-1)/(x-1)=1
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