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高一数学三角函数化简为题
√[(sin^2 α)(1+cotα)+(cos^2 α)(1+tanα)]
人气:377 ℃ 时间:2020-09-30 23:24:53
解答
√[(sin^2 α)(1+cotα)+(cos^2 α)(1+tanα)]
=√[(sin)^2+sinacosa+sinacosa+(cosa)^2]
=√(sina+cosa)^2
=|sina+cosa|
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