在溶液中加入足量的Na2O2后仍能大量共存的离子组是( )
A. NH4+Ba2+ Cl- NO3-
B. K+ AlO2- Cl- SO42-
C. Ca2+ Mg2+ NO3- HCO3-
D. Na+ Cl- CO32- SO32-
人气:426 ℃ 时间:2020-06-06 13:39:23
解答
A.在溶液中加入足量的Na2O2后生成NaOH,与NH4+结合生成弱电解质,则不能共存,故A错误;B.该组离子在碱性溶液中不反应,则能共存,故B正确;C.在溶液中加入足量的Na2O2后生成NaOH,NaOH与HCO3-反应生成水和碳酸根...
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