平方项与绝对值项均恒非负,两非负项之和=0,两非负项都=0
2a+b+3=0
b-1=0
解得a=-2 b=1
3a-3[2b-8+(3a-2b-1)-a]+1
=3a-6b+24-9a+6b+3+3a+1
=-3a+28
=-3×(-2)+28
=6+28
=34