因式分解:15abc-5bc² m(a-5)+2(5-a) (a-4)(a+1)+3a 4+12(x-y)+9(x-y)²
人气:353 ℃ 时间:2020-04-14 08:38:24
解答
15abc-5bc² =5bc(3a-c)m(a-5)+2(5-a)=m(a-5)-2(a-5)=(m-2)(a-5)(a-4)(a+1)+3a =a²-3a-4+3a=a²-4=(a+2)(a-2)4+12(x-y)+9(x-y)²=2²+2*3(x-y)+[3(x-y)]²=[2+3(x-y)]&...
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