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因式分解:
(1)(x-y+z)2-(x+y-z)2
(2)x3+6x2+11x+6.
人气:388 ℃ 时间:2020-06-02 05:02:35
解答
(1)原式=【(x-y+z)+(x+y-z)】【(x-y+z)-(x+y-z)】=2x•(-2y+2z)=-4x(y-z);
(2)原式=x3+6x2+9x+2x+6
=x(x+3)2+2(x+3)
=(x+3)[x(x+3)+2]
=(x+3)(x2+3x+2)
=(x+3)(x+1)(x+2).
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