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计算 ①2(x^2)^3*x^2-3(x^3)^2+5x^2*x^6 ②(-2^2)*(-2)^2
人气:208 ℃ 时间:2020-02-04 08:35:20
解答
2(x^2)^3*x^2-3(x^3)^2+5x^2*x^6
=2x^6*x^2-3x^6+5x^2*x^6
=2x^(6+2)-3x^6+5x^(2+6 )
=2x^8-3x^6+5x^8
=2x^8+5x^8-3x^6
=7x^8-3x^6
(-2^2)*(-2)^2
=-4*4
=-16
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