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1/(2根号1+1根号2)+1/(3根号2+2根号3)+.+1/(100根号99+99根号100)
人气:442 ℃ 时间:2020-06-15 12:51:43
解答
1/(2根号1+1根号2)=(2根号1-1根号2)/(4-2)=根号1-(根号2)/21/(3根号2+2根号3)=(3根号2-2根号3)/(18-12)=(根号2)/2-(根号3)/31/(2根号1+1根号2)+1/(3根号2+2根号3)+.+1/(100根号99+99根号100) =根号1-(根号)/2+(根号)...
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