=∫-x²/5x² dx
=∫(-1/5)dx
=-x/5+C
=∫9^x*e^xdx
=∫(9e)^xdx
=1/ln(9e)*∫ln(9e)*(9e)^xdx
=(9e)^x/ln(9e)+C不好意思 应该是∫ (2^x-3^x)/5^xdx∫3^2x乘以e^xdx 求答案啊啊 谢谢∫ (2^x-3^x)/5^xdx=∫ (2/5)^xdx-∫ (3/5)^xdx=(2/5)^x/ln(2/5)(3/5)^x/ln(3/5)+C