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分解 2x^3-4x^2y-x^2z+2xy^2+2xyz-y^2z求过程
人气:128 ℃ 时间:2020-02-05 23:55:11
解答
2x^3-4x^2y-x^2z+2xy^2+2xyz-y^2z
=(2x^3-4x^2y+2xy^2)-(x^2z-2xyz+y^2z)
=2x(x^2-2xy+y^2)-z(x^2-2xy+y^2)
=2x(x-y)^2-z(x-y)^2
=(x-y)^2(2x-z)
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