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求z={ln(xy)}^0.5的偏导数,
人气:110 ℃ 时间:2020-05-12 04:20:16
解答
Zx=1/2*[ln(xy)]^(-1/2)*[1/(xy)]*y
=1/(2x)*[ln(xy)]^(-1/2)
Zy=1/2*[ln(xy)]^(-1/2)*[1/(xy)]*x
=1/(2y)*[ln(xy)]^(-1/2)
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