> 数学 >
已知x2+x+3=0，求x5+3x4+2x3+2x2-10x的值．
人气：172 ℃　时间：2019-10-19 04:13:12
解答
∵x2+x+3=0，
∴x2+x=-3，
x5+3x4+2x3+2x2-10x
=x3（x2+x）+2x4+2x3+2x2-10x
=-3x3+2x4+2x3+2x2-10x
=2x4-x3+2x2-10x
=2x2（x2+x）-3x3+2x2-10x
=-3x3-4x2-10x
=-3x（x2+x）-x2-10x
=9x-x2-10x
=-x2-x
=-（x2+x）
=3．
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版