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数学
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(-1+1/100)x(-1+1/101)x(-1+1/102)x...x (-1+1/2011)计算
人气:169 ℃ 时间:2020-04-15 13:00:59
解答
(-1+1/100)x(-1+1/101)x(-1+1/102)x...x (-1+1/2011)
=(-1)的1912次方 ×(1-1/100)×(1-1/101)×(1-1/102)×...×(1-1/2010)×(1-1/2011)
=(99/100)×(100/101)×(101/102)×...×(2009/2010)×(2010/2011) (注:相邻两项分子分母相消)
=99/2011
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