> 数学 >
不解方程组2x+y=6;x-3y=1 求代数式x(x-3y)的平方-(x+y)(3y-x)的三次方的值
人气:260 ℃ 时间:2019-08-20 09:49:37
解答
2x+y=6
x-3y=1
x(x-3y)²-(x+y)(3y-x)³
=x(x-3y)²+(x+y)(x-3y)³
=(x-3y)²[x+(x+y)(x-3y)]
带入 x-3y=1得
=x+x+y
=2x+y
=6
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版