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f(x)=cos(2x-π/3)-cos2x-1化简
人气:331 ℃ 时间:2020-05-26 04:51:46
解答
f(x)=cos(2x-π/3)-cos2x-1
= cos2xcosπ/3+sin2xsinπ/3-cos2x-1
= 1/2cos2x+√3/2sin2x-cos2x-1
= -1/2cos2x+√3/2sin2x-1
= -cos2xcosπ/3+sin2xsinπ/3-1
= -cos(2x+π/3)-1
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