(1+1/1*3)*(1+1/2*4)*(1+1/3*5)*...*(1+1/98*100)怎么做(1+1/1*3)*(1+1/2_数学解答

(1+1/1*3)*(1+1/2*4)*(1+1/3*5)*...*(1+1/98*100)怎么做
(1+1/1*3)*(1+1/2*4)*(1+1/3*5)*...*(1+1/98*100)怎么做

人气：333 ℃　时间：2019-10-19 17:44:31

解答

原式=（2²*3²*4²*...*97²*98²*99²）/(1*2*3²*4²*...*98²*99*100)
=2²*99²/(1*2*99*100)
=2*99/100
=99/50