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∫ [上限π,下限0] |cosx| dx
人气:230 ℃ 时间:2020-04-07 05:17:20
解答
∫(0,π)|cosx|dx
= ∫(0,π/2)cosxdx + ∫(π/2,π)(-cosx)dx
= [sin(π/2)-sin0] -[sinπ-sin(π/2)]
= 2
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