知道弧长C=6000mm,弦高H=300mm,求弧的半径R?
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=15000
R1=14949.39
R2=14949.73
R3=14949.73
R=14949.73