2/3√(9x)+ 6√(x/4)- 2x√(1/x)
(5+√6)(√50-√12)
1/2√(27)*√(1/45)÷(-3/2√5/6)
(6√0.5 - 3√1/3)-4(√1/8-√48)
(√20+√5)/√5 - √1/3 × √12
人气:337 ℃ 时间:2020-04-08 16:19:06
解答
2/3√(9x)+ 6√(x/4)- 2x√(1/x)
=2√x+ 3√x- 2√x
=3√x
(5+√6)(√50-√12)
=(5+√6)[√2(5-√6)]
=√2(5+√6)(5-√6)
=√2(25-6)
=19√2
1/2√(27)*√(1/45)÷(-3/2√5/6)
=1/2*3√3*1/3*√(1/6)÷[-3/2√(5/6)
=1/2√3*√(1/6)÷[-3/2√(5/6)
=1/2√[3*(1/6)]÷[-3/2√(5/6)
=1/2√(1/2)]÷[-3/2√(5/6)
=√2/4÷[-3/2√(5/6)
=√2/4÷[-3/2*1/6√30]
=√2/4÷[-√30/4]
=-√2/4*4/√30
=-√2/√30
=-1/√15
=-√15/15
(6√0.5 -3√1/3)-4(√1/8-√48)
=(3√2 -√3)-(√2-16√3)
=3√2 -√3-√2+16√3
=2√2+ 15√3
(√20+√5)/√5 - √1/3 × √12
=(2√5+√5)/√5- √1/3 × 2 √3
=3√5/√5- √(3*1/3) ×2
=3-2
=1
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