计算:
(1)
()0.5+()−+(0.1)−2−3π0;
(2)
lg−lg+lg12.5−log89•log278.
人气:393 ℃ 时间:2020-03-28 12:00:22
解答
(1)原式=[(
)
2]
0.5+
[()3]−+(10
-1)
-2-3×1
=
++100−3=100
.
(2)原式=lg(
××)-
•=lg10-
=1-
=
.
推荐
- (25/9)0.5+0.1^-2+(64/27)^2/3=0//如何计算?
- 计算行列式1,1,1,1;2,3,4,5;4,9,16,25;16,27,64,125
- 脱式计算(能简便的简便) 2012×2010/2011 3.64÷4+4.36×0.25 (5/8+2/27)×8+11/27 41×9.9+4.1
- 计算:(25/9)^0.5+(64/27)^(1/3)+lg6+根号[(lg6)^2-lg36+1].
- 用简便方法计算:(0.25^9)*(2^20)*(25^9)*(64^3)
- 仿句:两岸的豆麦和河底的水草所发散出来的清香,夹杂在水气中扑面的吹来;月色便朦胧在这水气里.淡黑的起伏的连山,仿佛是踊跃的铁的兽脊似的,都远远的向船尾跑去了,但我却还以为船慢.
- 将所给的句子合并为一个宾语从句.When did he get up yesterday morning?(Do you know.)
- (x+1)2+(x+1)11=a0+a1(x+2)+a2(x+2)2+…+a10(x+2)10+a11(x+2)11,则a1=( ) A.-12 B.-10 C.9 D.11
猜你喜欢