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y²+3x=7,y³+x=3,求y等于几.
人气:119 ℃ 时间:2020-02-05 10:14:33
解答
y²+3x=7 x=(7-y²)/3y³+x=3 x=3-y³(7-y²)/3=3-y³3y³-y²-2=03y³-3y²+2y²-2=03y²(y-1)+2(y+1)(y-1)=0(y-1)(3y²+2y+2)=03y²+2y+2=3(y+ 1/3)...
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