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求证:sin(a+b)cosa-(1/2)[sin(2a+b)-sinb]=sinb
人气:484 ℃ 时间:2020-06-21 07:39:36
解答
sin(a+b)cosa - (1/2)[sin(2a+b) - sinb]
=sin(a+b)cosa - (1/2)[sin(a+b)cosa + cos(a+b)sina - sinb]
=(1/2)[sin(a+b)cosa - cos(a+b)sina - sinb]
=(1/2)sin(a+b-a) + (1/2)sinb
=sinb
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