> 数学 >
当x=2时,代数式ax^5+bx^3+cx+7的值是-10,当x=-2时,求代数式的值,过程是怎么样的?
人气:186 ℃ 时间:2020-04-29 15:09:58
解答
x=2
ax^5+bx^3+cx+7
=2^5a+2^3b+2c+7
=10
2^5a+2^3b+2c=10-7=3
x=-2
ax^5+bx^3+cx+7
=-2^5a-2^3b-2c+7
=-(2^5a+2^3b+2c)+7
=-3+7
=4
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