(x-2)分之(x-2)³-(x-1)²+1原式=(x-2)²-[(x-1)²-1]／(x-2)=(x-2)²-(x²-2x)／(x-2)=(x-2)²-[x(x-2)]/(x-2)=(x-2)²-x=x²-4x+4-x=x²-5x+4∵x²-5x-2007=0∴x...