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(-2)^3×(-1)^4-|-12|÷[-(-1/2)^2]
12xy+(3x^2-5xy)-2(3xy+2x^2)
3x^2+[x^2+(5x^2-2x)-2(x^2-3x)],其中x=2
人气:175 ℃ 时间:2020-04-07 11:01:16
解答
(-2)^3×(-1)^4-|-12|÷[-(-1/2)^2]=-8x1-12x(-4)=-8+48=40;
12xy+(3x^2-5xy)-2(3xy+2x^2)=12xy+3x^2-5xy-6xy-4x^2=xy-x^2;
3x^2+[x^2+(5x^2-2x)-2(x^2-3x)]=3x^2+[x^2+5x^2-2x-2x^2+6x]=
3x^2+[4x^2+4x]=7x^2+4x=7x2^2+4x2=7x4+8=28+8=36
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