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若3x^2-x=1,则6x^3+7x^2-5x+1990的值是
人气:363 ℃ 时间:2020-04-07 07:33:44
解答
3x^2-x=1
3x^2-x-1=0
6x^2-2x-2=0
6x^3+7x^2-5x+1990
=x(6x^2-2x-2)+9x^2-3x+1990
=9x^2-3x-3+1993
=3(3x^2-x-1)+1993
=0+1993
=1993
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