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若tanx/2=2/3,化简1-cosx+sinx/1+cosx+sinx
人气:268 ℃ 时间:2020-06-02 00:57:35
解答
tanx/2=2/3
(1-cosx+sinx)/(1+cosx+sinx)
=[(cosx/2+sinx/2)^2-(cos^2x/2-sin^2x/2)]/[(cosx/2+sinx/2)^2+(cos^2x/2-sin^2x/2)]
=2(cosx/2+sinx/2)*sinx/2/2(cosx/2+sinx/2)*cosx/2
=sinx/2/cosx/2
=tanx/2
=2/3
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