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三角形三个角比求出三边比 公式
人气:194 ℃ 时间:2020-06-03 04:40:03
解答
设三个角比为A:B:C = x:y:z.
则,A = xt,B = yt,C = zt,
其中,t为待定常数.
因PI = A + B + C = t(x+y+z),
t = PI/(x+y+z).
A = xPI/(x+y+z),
B = yPI/(x+y+z),
C = zPI/(x+y+z).
再利用正弦定理,
a:b:c = sin(A):sin(B):sin(C) = sin[xPI/(x+y+z)] :sin[yPI/(x+y+z)] :sin[zPI/(x+y+z)]
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