(1)(1/a+1/b)^2÷(1/a^2-1/b^2) (2)(a+b/a-b)^2*2a-2b/3a+3b -a^2/a^2-b^2÷a/b
人气:444 ℃ 时间:2020-04-18 11:37:25
解答
(1)(1/a+1/b)^2÷(1/a^2-1/b^2) =(1)(1/a+1/b)^2÷【(1/a-1/b)*(1/a+1/b) 】=(1/a+1/b)÷(1/a-1/b)=(a+b)/(b-a)(2)(a+b/a-b)^2*2a-2b/3a+3b -a^2/a^2-b^2÷a/b=2(a+b)/[3(a-b)]-ab/(a^2-b^2)=(2a^2+2b^...
推荐
猜你喜欢