弧长C=12.8米,弦长L=11.4米,求高度H?
弧半径为R.
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=7
R1=7.605
R2=7.759
R3=7.767
R4=7.767
R=7.767米
H=R-(R^2-(L/2)^2)^0.5
=7.767-(7.767^2-(11.4/2)^2)^0.5
=2.491米