(2)根据断路状态时,R2=
| U2 |
| I2 |
| 3.2 |
| 0.8 |
断路前
R2的电压U1=I1R2=0.75×4V=3V
流过R3的电流I3=
| U1-Uv |
| R3 |
| 3-2 |
| 4 |
则R1=
| Uv |
| I3 |
| 2 |
| 0.25 |
(3)根据闭合电路欧姆定律得:
E=U1+(I1+I2)r=3+r ①
E=U2+I2′r=3.2+0.8r ②
由①②联立组成方程组,解得E=4V,r=1Ω
故答案为:(1))R1断路.(2)R1=8Ω,R2=4Ω(3)E=4V,r=1Ω

| U2 |
| I2 |
| 3.2 |
| 0.8 |
| U1-Uv |
| R3 |
| 3-2 |
| 4 |
| Uv |
| I3 |
| 2 |
| 0.25 |