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解分式不等式(x+2)/(x+1)+(x+3)/(x+2)≥(x+1)/x+(x+4)/(x+3)
人气:221 ℃ 时间:2020-06-07 07:03:35
解答
(x+1+1)/(x+1)+(x+2+1)/(x+2)>=(x+1)/x+(x+3+1)/(x+3)1+1/(x+1)+1+1/(x+2)>=1+1/x+1+1/(x+3)1/(x+1)+1/(x+2)>=1/x+1/(x+3)1/(x+2)-1/(x+3)>=1/x-1/(x+1)1/(x^2+5x+6)-1/(x^2+x)>=0(-4x-6)/(x+2)(x+3)x(x+1)>=0(2x+3)...
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