> 数学 >
分解因式:
①x2y2-5x2y-6x2
②(p2+q22-4p2q2
③(a-b)4-3(a-b)2-10   
④x2-y2+4y-4.
人气:172 ℃ 时间:2020-06-02 20:10:01
解答
①x2y2-5x2y-6x2 =x2(y2-5y-6)=x2(y-6)(y+1);
②(p2+q22-4p2q2=(p2+q2+2pq)(p2+q2-2pq)=(p+q)2(p-q)2
③(a-b)4-3(a-b)2-10=[(a-b)2-5][(a-b)2+2]; 
④x2-y2+4y-4=x2-(y2-4y+4)=x2-(y-2)2=(x+y-2)(x-y+2).
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版