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数学
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求y=-x²-1/2x+2的最大值
人气:415 ℃ 时间:2020-07-22 12:11:09
解答
y=-x²-(1/2)x+2
=-(x²+ x/2)+2
=-(x² +x/2 +1/16) +33/16
=-(x +1/4)² +33/16
当x=-1/4时,y有最大值ymax=33/16
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