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计算:(a^n b^4)³·a^5 b^2n-9 -(a^n+1 b)³·(ab^n)²
人气:245 ℃ 时间:2020-02-04 08:59:25
解答
(a^n b^4)³·a^5 b^2n-9 -(a^n+1 b)³·(ab^n)²
=a^3n b^12·a^5 b^2n-9 -a^(3n+3) b³·a²b^2n
=a^(3n+5) b^(2n+3) -a^(3n+5) b^(2n+3)
=0
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