因式分解:x^3+3x^2+6x+8
人气:236 ℃ 时间:2020-02-20 15:06:54
解答
x^3-3x^2-6x+8
=x^3-4x^2+x^2-6x+8
=x^2(x-4)+(x-4)(x-2)
=(x-4)(x^2+x-2)
=(x-4)(x+2)(x-1)你的题目抄错了x³+3x²+6x+8
=x²+3x²+6x+x+8
=4x²+7x+8我已经算出来了,答案是(x+2)(x^2+4),虽然你错了,错在因式分解结果要写成乘积形式,但还是要谢谢你哦!不用谢!
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