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十字相乘法分解因式(a²+2a+3)²-13(a²+2a+3)+22
人气:242 ℃ 时间:2020-05-09 16:36:19
解答
1 -2
1 -11
所以 (a²+2a+3)²-13(a²+2a+3)+22
=(a²+2a+3-2)(a²+2a+3-11)
=(a²+2a+1)(a²+2a-8)
1 1 1 4
1 1 1 -2
所以 (a²+2a+3)²-13(a²+2a+3)+22
=(a+1)²(a+4)(a-2)
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