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已知:x/y=4/5,求y²/(x²-xy+y²)的值
人气:118 ℃ 时间:2019-11-17 07:27:10
解答

x/y=4/5
∴x=4/5y

y²/(x²-xy+y²)
=y²/[(4/5y)²-(4/5y)y+y²]
=y²/[16/25y²-4/5y²+y²]
=y²/(-4/25y²+y²)
=y²/(21/25y²)
=25/21
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