求证tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)=-tanα_数学解答

求证tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)=-tanα

人气：274 ℃　时间：2020-04-02 04:21:34

解答

tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)
=(-tana)(-sina)cosa/(-cosa)sina
=-tana

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