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2cos2x+2sin2x怎么化简
人气:115 ℃ 时间:2020-06-23 05:22:09
解答
2cos2x+2sin2x
=2√2(sin2x (√2/2) + cos2x (√2/2) )
=2√2(sin2xcosπ/4 + cos2xsinπ/4)
=2√2sin(2x+π/4)
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