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求:lim(x->0)[1+e-(1+x)^(1/x)]^(1/x)
lim(x->0)(1+x)^(1/x)=e;
于是式子变为:1^无穷,不定式.
人气:113 ℃ 时间:2020-05-27 08:29:20
解答
=limexp{ln[1+e-(1+x)^(1/x)]/x}=exp{lim[e-(1+x)^(1/x)]/x}(等价无穷小的替换)=exp{lim[e-e^(ln(1+x)/x)]/x}=exp{lim[e-e^(1-x/2+o(x))]/x}(泰勒公式求极限)=exp{elim[1-e^(-x/2+o(x))]/x}=exp{elim[1-(1-x/2+o...
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