已知:2x+y=6,x-3y=1 求7y(x-3y)(x-3y)-2(3y-x)(3y-x)
人气:412 ℃ 时间:2020-05-22 14:52:57
解答
7y-2
=2x+y-2x+6y
=(2x+y)-2(x-3y)
=6-2
=4
7y(x-3y)(x-3y)-2(3y-x)(3y-x)
=7y(x-3y)(x-3y)-2(x-3y)(x-3y)x-3y=1
=7y-2 7y-2=4
=4
推荐
- 已知:2x+y=6,x-3y=1,求7y(x-3y)^2-2(3y-x)^2
- 若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
- 提公因式:已知2x+y=6 x-3y=1 ,求7y(x-3y)²-2(3y-x)³的值.
- 解下列方程组{3x+7y=6,2x-7y=4;(2){y=3x,2x+3y=22.
- (1)若|2x+6|+|y-1|=0,则2x+3y=?(2)若|x|=1/3,y²=4,且xy>0,则3x-7y=?
- 要使不等式x方-2ax+1大于等于二分之一倍的x-1的平方对一切实数x都成立,求实数a的
- 已知数列{an}的前n项和为Sn,且a1+2a2+3a3+…+nan=(n-1)Sn+2n(n∈N*),求数列{an}通项公式.
- 单词填空根据首字母提示,写出单词 I have n____ important to do.
猜你喜欢