1.1000mL (1L) 98%的浓硫酸:
质量1.84*1000 = 1840 g
H2SO4的质量:1840*98% = 1803 g
H2SO4的物质的量:1803/98 = 18.4 mol
H2SO4的物质的量浓度:18.4/1 = 18.4 mol/L
2.溶液质量:1840*2 = 3680 g
溶液的质量分数:1803/3680 = 49%
3.溶液的质量:1840 + 1000 = 2840 g
溶液的质量分数:1803/2840 = 63.5%
4.1*1 = 18.4V
v = 0.0543 L = 54.3 mL