1)f(x)=2sin(x+π/4)^2-√3cos2x-1=-√3cos2x-[1-2sin(x+π/4)^2]=-√3cos2x-sin2x=-2sin(2x+π/3)最小值为-2,最大值为2最小正周期为T=π2)h(x)=f(x+t)==-2sin(2x+2t+π/3)关于点（-π/6,0)对称故2×(-π/6)+2t+π/3...