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log8^9.log27^32+lg25+lg2.lg50+lg2.lg2
人气:128 ℃ 时间:2020-03-14 13:20:25
解答
log8^9.log27^32+lg25+lg2.lg50+lg2.lg2 换底公式=(2lg3/3lg2)*(5lg2/3lg3)+2lg5+lg2(1+lg5)+lg2*lg2=10/9+2lg5+lg2+lg2lg5+lg2*lg2=10/9+2lg5+lg2+lg2(lg5+lg2)=10/9+2lg5+2lg2=10/9+2(lg5+lg2)=10/9+2=28/9请参考...
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