计算(x+y)(x²+y²)(x-y)(x的4次方+y的4次方),(a-1)(-a-1)_数学解答

计算(x+y)(x²+y²)(x-y)(x的4次方+y的4次方),(a-1)(-a-1)

人气：431 ℃　时间：2020-01-25 10:47:34

解答

原式=(x²-y²)(x²+y²)(x^4+y^4)
=(x^4-y^4)(x^4+y^4)
=x^8-y^8
原式=(-1+a)(-1-a)
=(-1)²-a²
=1-a²